Add $ -r^2-2r-4 $ to both sides of the given congruence to obtain $ 2r\equiv -3\pmod{55} $. We can multiply both sides by $ 28 $ to get $ 56r \equiv -3\cdot 28\pmod{55} $. Subtracting $ 55r $ from the left-hand side and adding $ 2\cdot 55=110 $ to the right-hand side gives $ r\equiv 26\pmod{55} $. Thus $ r=26+55k $ for some integer $ k $. Solving $ 26+55k\geq 1000 $, we find that $ k=18 $ is the smallest value of $ k $ for which $ r $ has four digits. Thus the minimum four-digit value of $ r $ is $ 26+55(18)=\boxed{1016} $.