Reading from the equation, we see that the center of the ellipse is $ (6, 3), $ the length of the semimajor axis is $ \sqrt{25} = 5, $ and the length of the semiminor axis is $ \sqrt{9} = 3 $. Then, the distance from the center to each of the foci must be $ \sqrt{5^2 - 3^2} = 4 $. The major axis is parallel to the $ x $-axis, so the coordinates of the two foci are $ (6-4,3)=(2,3) $ and $ (6+4,3)=(10,3) $. The one with the larger $ x $-coordinate is $ \boxed{(10,3)} $.