Factors and Multiples Count
How many of the following numbers are factors of 34 or multiples of 7?
1, 2, 3, 4, 8, 14, 17, 29, 56, 91
- 1
- 2
- 3
- +
- 4
- 5
- 6
- -
- 7
- 8
- 9
- $\frac{a}{b}$
- .
- 0
- =
- %
- $a^n$
- $a^{\circ}$
- $a_n$
- $\sqrt{}$
- $\sqrt[n]{}$
- $\pi$
- $\ln{}$
- $\log$
- $\theta$
- $\sin{}$
- $\cos{}$
- $\tan{}$
- $($
- $)$
- $[$
- $]$
- $\cap$
- $\cup$
- $,$
- $\infty$
Solution
We can check each number one by one.
1: 1 is a factor of 34 since $ 1\cdot34=34 $ .
2: 2 is a factor of 34 since $ 2\cdot17=34 $ .
3: 3 is not a factor of 34 since there is no number that can be multiplied by 3 to get 34. ( $ 34\div3 $ gives a quotient of 11 and a remainder of 1.) There is also no number that can be multiplied by 7 to get 3 ( $ 3\div7 $ gives a quotient of 0 and a remainder 3.)
4: 4 is not a factor of 34 since there is no number that can be multiplied by 4 to get 34. ($ 34 \div 4 $ gives a quotient of 8 and a remainder of 2.) There is also no number that can be multiplied by 7 to get 4. ($ 4 \div 7 $ gives a quotient of 0 and a remainder of 4.)
8: 8 is not a factor of 34 since there is no number that can multiply it to get 34 ( $ 34\div8 $ gives a quotient of 4 and a remainder of 2) and is not a multiple of 7 since there is no number that can multiply 7 to get 8 ( $ 8\div7 $ gives a quotient of 1 and a remainder 1).
14: 14 is a multiple of 7 since $ 7\cdot2=14 $ .
17: 17 is a factor of 34 since $ 17\cdot2=34 $ .
29: 29 is not a factor of 34, since there is no number that can multiply it to get 34 ( $ 34\div29 $ gives a quotient of 1 and a remainder of 5) and is not a multiple of 7 since there is no number that can multiply 7 to get 29 ( $ 29\div7 $ gives a quotient of 4 and a remainder 1).
56: 56 is a multiple of 7 since $ 7\cdot8=56 $ .
91: 91 is a multiple of 7 since $ 7\cdot13=91 $ .
So, $ \boxed{6} $ of the 10 numbers are factors of 34 or multiples of 7.