There are only two possible occupants for the driver's seat. After the driver is chosen, there are three remaining people who can sit in the other front seat. Then the three remaining people can sit in the back seats in any arrangement. There are three choices of people to sit in the first back seat, two choices of people to sit in the next back seat, and one person to sit in the last back seat. Therefore, there are $ 2 \cdot 3 \cdot 3 \cdot 2 \cdot 1 = \boxed{36} $ possible seating arrangements.