As we are told, we want to find all values of $ n>1 $ such that $ n $ divides into $ 171-80 = 91 $ and $ n $ also divides into $ 468 - 13 = 455 $. We notice that $ 455 = 5 \cdot 91 $, so it follows that if $ n $ divides into $ 91 $, then it must divide into $ 455 $. Then, we only need to find the factors of $ 91 $, which are $ \{1,7,13,91\} $. Summing the factors other than $ 1 $ gives $ 7 + 13 + 91 = \boxed{111} $.