Consider points $ P $, $ Q $, and $ R $. If the slope between point $ P $ and point $ Q $ is the same as the slope between point $ Q $ and point $ R $, $ P $, $ Q $, and $ R $ are collinear. So we must find the slopes between every pair of possible points. Let us name the points: $ A=(2,2) $, $ B=(9,11) $, $ C=(5,7) $, and $ D=(11,17) $. We make a chart of all possible pairs of points and calculate the slope: \begin{array}{c|c} \text{Points} & \text{Slope}\\ \hline A,B& \frac{11-2}{9-2}=\frac{9}{7} \\ A,C & \frac{7-2}{5-2}=\frac{5}{3} \\ A,D & \frac{17-2}{11-2}=\frac{15}{9}=\frac{5}{3} \\ B,C & \frac{7-11}{5-9}=\frac{-4}{-4}=1 \\ B,D & \frac{17-11}{11-9}=\frac{6}{2}=3 \\ C,D & \frac{17-7}{11-5}=\frac{10}{6}=\frac{5}{3} \end{array} As we can see, the slopes between $ A $ and $ C $, $ A $ and $ D $, and $ C $ and $ D $ are the same, so $ A $, $ C $, and $ D $ lie on a line, Thus $ B $, or the point $ \boxed{(9,11)} $, is not on the line.