Probability of Aces
A standard deck of 52 cards has 13 ranks (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King) and 4 suits ($ \spadesuit $, $ \heartsuit $, $ \diamondsuit $, and $ \clubsuit $), such that there is exactly one card for any given rank and suit. Two of the suits ($ \spadesuit $ and $ \clubsuit $) are black and the other two suits ($ \heartsuit $ and $ \diamondsuit $) are red. The deck is randomly arranged. What is the probability that the top two cards are both Aces?
- 1
- 2
- 3
- +
- 4
- 5
- 6
- -
- 7
- 8
- 9
- $\frac{a}{b}$
- .
- 0
- =
- %
- $a^n$
- $a^{\circ}$
- $a_n$
- $\sqrt{}$
- $\sqrt[n]{}$
- $\pi$
- $\ln{}$
- $\log$
- $\theta$
- $\sin{}$
- $\cos{}$
- $\tan{}$
- $($
- $)$
- $[$
- $]$
- $\cap$
- $\cup$
- $,$
- $\infty$