Since $ f(x) $ is an odd function, $ f(-x) = -f(x) $. In particular, \[f(3) = -f(-3) = -5.\]Therefore, the graph of $ f(x) $ must also pass through the point $ \boxed{(3,-5)} $. Also, \[f(0) = -f(0),\]so $ f(0) = 0 $. Thus, $ \boxed{(0,0)} $ is also an acceptable answer. (This is assuming that $ f(x) $ is defined at $ x = 0 $.)